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Sweet! Thank You Both!
![]() "Sue Mosher [MVP-Outlook]" wrote: The InStrRev() function will find the first period, searching from the end of the string: strAtmtName = Atmt.FileName intLoc = InStrRev(strAtmtName, ".") If intLoc 0 Then fName = Left(strAtmtName , intLoc - 1) fExt = Mid(strAtmtName , intLoc + 1) Else fName = strAtmtName fExt = "" End If I'd suggest that you read up on the InStrRev, Left and Mid functions in Help, now that you've seen them in action. -- Sue Mosher, Outlook MVP Author of Microsoft Outlook 2007 Programming: Jumpstart for Power Users and Administrators http://www.outlookcode.com/article.aspx?id=54 "Rob" wrote in message ... I was told I should use this section for my request for help so here I go again. I am trying to seperate the extension from a file name so that what I am left with is an extension and a file name that's stored in String Variables for re-use later on in the macro. I have no clue how to really do this but what I have gotten so far is below and apparently that's not all that right either. Can someone please show me the right way of doing this so I can have it to refer to in the future, because I can't seem to find it with the help files of Outlook? Dim Item As Object Dim Atmt As Attachment Dim fExt As String Dim fName As String For Each Atmt In Item.Attachments fExt = Right(Atmt.FileName, 4) 'returns the .??? extension fName = For the fName above I tried to do a Trim/RTrim & LTrim but all I get in the help keeps referring to (Expression) with no clue as to what expression is the correct expression. Also Apparently there is a possibility of there being more than three letters and a dot for the extension so now I have to look at using "InstrRev" to find the dot and then figure out the right side verses the left side. What if there's more than one dot in the name of the file, wouldn't that throw it all off??? I have NO idea what to do with that at all. When I do the F1 deal in the macro editor, well I'm lost at that too. Thank You Very Much for Your Time and Help. Rob |
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